Project Euler – Problem 6 Solution

Problem: The sum of the squares of the first ten natural numbers is,

1^2 + 2^2 + … + 10^2 = 385

The square of the sum of the first ten natural numbers is,

(1 + 2 + … + 10)^2 = 55^2 = 3025

Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 – 385 = 2640.

Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.

*https://projecteuler.net/problem=6

PHP;

$a = 385;
$b = 55;

for ($i = 11; $i <= 100; $i++) {
    $a += $i**2;
    $b += $i;
}

echo ($b**2) - $a;

Javascript;

'use strict';

let a = 325;
let b =  55;

for (let i = 11; i <= 100; i++) {
    a += i**2;
    b += i;
}

console.log((b**2) - a);