Project Euler – Problem 6 Solution
Problem: The sum of the squares of the first ten natural numbers is,
1^2 + 2^2 + … + 10^2 = 385
The square of the sum of the first ten natural numbers is,
(1 + 2 + … + 10)^2 = 55^2 = 3025
Hence the difference between the sum of the squares of the first ten natural numbers and the square of the sum is 3025 – 385 = 2640.
Find the difference between the sum of the squares of the first one hundred natural numbers and the square of the sum.
*https://projecteuler.net/problem=6
PHP;
$a = 385; $b = 55; for ($i = 11; $i <= 100; $i++) { $a += $i**2; $b += $i; } echo ($b**2) - $a;
Javascript;
'use strict'; let a = 325; let b = 55; for (let i = 11; i <= 100; i++) { a += i**2; b += i; } console.log((b**2) - a);